Velocity | |
v = velocity v_{o} = velocity original f = force m = mass (of projectile) t = time total(in seconds) | v - v_{o} = (f/m)t |
Distance | |
x = distance x_{o} = position of x @ t_{o} (usually 0) t = time total (in seconds) t_{o} = starting time (usually 0) g = gravity, acceleration of (9.802 ms^{2}, or 32.16 ft.sec^{2} v_{o} = velocity original | x = x_{o} + (v_{o}t) - 1/2(gt^{2}) And we can simplify to below, becuase we assume x_{o} = 0. x = (v_{o}t) - ^{1}/_{2}(gt^{2}) And we can simplify to below, becuase we assume v_{o} = 0. Since we assume the projectile starts motion from a standstill. x = ^{1}/_{2}(gt^{2}) |
Projectile Motion Description - It's ok, I don't understand this either. | |
g = gravity, acceleration of (9.802 ms^{2}, or 32.16 ft.sec^{2} z = vertical rise of projectile (height) v_{zo} = velocity, original, in the z-axis (height) v_{xo} = velocity, original, in the x-axis (distance) | z = (v_{zo}/v_{xo}) - 1/2(g/v_{xo}^{2})x^{2} |
Maximum Altitude Achieved | |
z_{m} = maximum altitude v_{zo} = velocity, original, in the z-axis (height) v_{xo} = velocity, original, in the x-axis (distance) |
z_{m} = (v_{zo}^{2})/2g |
Maximum Distance Achieved | |
x_{m} = maximum distance v_{zo} = velocity, original, in the z-axis (height) v_{xo} = velocity, original, in the x-axis (distance) g = gravity, acceleration of (9.802 ms^{2}, or 32.16 ft.sec^{2} |
x_{m} = 2(v_{zo}v_{xo}/g) |
Equation of Trajectory | |
z = height b = frictional force constant (air resistance) g = gravity, acceleration of (9.802 ms^{2}, or 32.16 ft.sec^{2} m = mass of projectile v_{zo} = velocity, original, in the z-axis (height) v_{xo} = velocity, original, in the x-axis (distance) |
z = {(mg/bv_{xo})+(v_{zo}xo)}x-{m^{2}g/b^{2}ln (mv_{xo}/[mv_{xo}-bx])} |